3.OA.1
“Interpret products of whole numbers, e.g., interpret 5 x 7 as the total number of objects in 5 groups of 7 objects each. For example, describe a context in which a total number of objects can be expressed as 5 x 7.”
Section 1, question 1: the 4 baskets of 6 apples become 4 × 6 = 24.
3.OA.2
“Interpret whole-number quotients of whole numbers, e.g., interpret 568 as the number of objects in each share when 56 objects are partitioned equally into 8 shares, or as a number of shares when 56 objects are partitioned into equal shares of 8 objects each. For example, describe a context in which a number of shares or a number of groups can be expressed as 56 ÷ 8.”
Leo's problem in Section 3, where 28 cards are shared equally onto 4 binder pages.
3.OA.3
“Use multiplication and division within 100 to solve word problems in situations involving equal groups, arrays, and measurement quantities, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem.'”
Both Section 3 stories: 5 packs of 8 stickers and 28 cards across 4 pages, each solved with a letter for the unknown.
3.OA.4
“Determine the unknown whole number in a multiplication or division equation relating three whole numbers. For example, determine the unknown number that makes the equation true in each of the equations 8 x ? = 48, 5 = _ ÷ 3, 6 x 6 = ?.”
The six missing-number equations in Section 2, from 7 × ______ = 42 through 9 × ______ = 81.
3.OA.5
“Apply properties of operations as strategies to multiply and divide.² Examples: If 6 x 4 = 24 is known, then 4 x 6 = 24 is also known. (Commutative property of multiplication.) 3 × 5 × 2 can be found by 3 x 5 = 15, then 15 x 2 = 30, or by 5 x 2 = 10, then 3 x 10 = 30. (Associative property of multiplication.) Knowing that 8 x 5 = 40 and 8 x 2 = 16, one can find 8 x 7 as 8 × (5 + 2) = (8×5) + (8 × 2) = 40 + 16 = 56. (Distributive property.)”
Question 7 in Section 2, where the fact family for 4, 9, and 36 turns on writing 9 × 4 after 4 × 9.
3.OA.6
“Understand division as an unknown-factor problem. For example, find 32÷8 by finding the number that makes 32 when multiplied by 8.”
Section 2 items such as 36 ÷ ______ = 9 and ______ ÷ 6 = 7, which are solved by finding the unknown factor.
3.OA.7
“Fluently multiply and divide within 100, using strategies such as the relationship between multiplication and division (e.g., knowing that 8 × 5 = 40, one knows 40 ÷ 5 = 8) or properties of operations. By the end of Grade 3, know from memory all products of two one-digit numbers.”
Every equation on the page stays within 100, from 4 × 6 in Section 1 to 9 × 9 = 81 in Section 2.