Partitioning Six-Digit Numbers

Year 5 MathsPlace Value5 pages

About this worksheet

Thirty-six partitioning questions for Year 5 run across three pages, with a two-page answer key. Pupils first combine parts into one number, such as 500,000 + 9,000 + 42 = 509,042. Then they find the missing part in equations like 705,412 = 700,000 + ? + 412. The last page is non-standard partitioning, for example 345,678 = 340,000 + 5,678 and 729,400 = ? + 129,400. Three digit-value questions finish it. Every number is below 1,000,000, in line with the England National Curriculum statement on numbers to 1 000 000.

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Curriculum objectives covered

Number - number and place value

โ€œRead, write, order and compare numbers to at least 1 000 000 and determine the value of each digitโ€

Every question depends on the value of each digit, and questions 34 to 36 ask for it directly.

What's inside this worksheet

Warm Up: Place Value Parts

Twelve additions of three parts, such as 620,000 + 5,000 + 300 and 850,000 + 7,000 + 19. Pupils write the six-digit total.

Level Up: Missing Parts

Twelve equations with one part missing. In some the blank sits in the middle, as in 430,875 = 400,000 + ? + 875.

Beat the Clock: Non-Standard Partitioning

Nine splits where the given part is not a single place value, such as 483,210 = 450,000 + ?. Then the value of 7 in 472,109, the value of 6 in 608,432, and 50 ten thousands + 408.

Answers

All 36 answers, one per line, in question order.

How teachers use it

Spot the placeholders

Question 3 gives 500,000 + 9,000 + 42. Ask pupils where the zeros go in 509,042 before they start, because placeholders cause most errors on page 1.

Build it with counters

For the missing-part questions, make 705,412 with place value counters and take away 700,000 and 412. The 5,000 left over answers question 16.

More than one split

Question 26 splits 612,500 into 500,000 + 112,500. Ask pairs to find three other splits of the same number and compare them on the board.

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